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The following is a proposition based on infinite series based on Ramanujan’s   Series Of: 1+2+3+4+5+6+7+………..= -1/12                           _(i) But I am getting It wrong somewhere . could anyone please me find out my mistake ? Here it goes :: S=1 2 +2 2 +3 2 +4 2 +5 2 +6 2 +……………………. Upto infinity S=1+4+9+16+25+36+49+64+81+100+…………… S=1+(2+2)+(3+6)+(4+12)+(5+20)+(6+30)+(7+42)+(8+56)+(9+72)+(10+90)+…………. S=(1+2+3+4+5+………..) + (2+6+12+20+30+42+……) From (i) S=-1/12+2x(1+3+6+10+15+21+………………) S+1/12=2x(1+3+6+10+15+21+………..)                                _(ii) S+1/12=2x(1+(2+1)+(3+3)+(4+6)+(5+10)+……..)    S+1/12=2x{(1+2+3+4………..)    + (1+3+6+10+15+…….)} S+1/12=2x (...

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EINSTEINS RIDDLE